[HackerRank] [C#] 1 Week Preparation Kit > Day 2 > Diagonal Difference
문제 : Diagonal Difference
사용언어 : C#
문제 내용
Given a square matrix, calculate the absolute difference between the sums of its diagonals.
For example, the square matrix arr is shown below:
1 2 3
4 5 6
9 8 9
The left-to-right diagonal = 1 + 5 + 9 = 15. The right to left diagonal = 3 + 5 + 9 + 17. Their absolute difference is |15 - 17| = 2.
Function description
Complete the diagonalDifference function in the editor below.
diagonalDifference takes the following parameter:
- int arr[n][m]: an array of integers
Return
- int: the absolute diagonal difference
Input Format
The first line contains a single integer, n, the number of rows and columns in the square matrix arr.
Each of the next n lines describes a row,arr[i], and consists of n space-separated integers arr[i][j].
Constraints
- -100 <= arr[i][j] <= 100
Output Format
Return the absolute difference between the sums of the matrix's two diagonals as a single integer.
Sample Input
3
11 2 4
4 5 6
10 8 -12
Sample Output
15
Explanation
The primary diagonal is:
11
5
-12
Sum across the primary diagonal: 11 + 5 - 12 = 4
The secondary diagonal is:
4
5
10
Sum across the secondary diagonal: 4 + 5 + 10 = 19
Difference: |4 - 19| = 15
Note: |x| is the absolute value of x
내 풀이
이중 for문으로 숫자를 하나씩 돌면서 대각선을 확인했다.
크기가 N * N 인 행렬이라고 했을 때,
(위에서부터) 오른쪽 -> 왼쪽 방향의 대각선은 x랑 y가 같고,
왼쪽 -> 오른쪽 방향의 대각선은 행렬 x, y의 합이 크기 N - 1이었다.
각각 구해서 계산하면 끝!
절댓값 구하기 : Abs()
private static int plus;
private static int minus;
private static int length;
public static int diagonalDifference(List<List<int>> arr)
{
length = arr.Count();
for(int i = 0; i < length; ++i)
{
for(int j = 0; j < length; ++j)
{
if(i == j)
{
plus += arr[i][j];
}
if(i + j == length - 1)
{
minus += arr[i][j];
}
}
}
return Math.Abs(plus - minus);
}
절댓값 구하기 / Abs()
public static int Abs(int num);
Math 클래스 안에 있는 함수.
사용 시에는 Math.Abs()로 썼다.